Cesium-137 has a decay constant of 0.0231 (a 30-year half-life). If you start with 15 pounds of cesium-137, how much will still be there 30 years later? Round to the nearest tenth.

N = 7.5 pounds

Step-by-step explanation:

Formula for the radioactive decay is given by,

Here, N = Final amount

N₀ = Initial amount

λ = Decay constant

t = Duration of decay

Now we can substitute the values from the given question,

N =

N =

N = 15(0.5)

N = 7.5 pounds

i think it's either c or d

step-by-step explanation: the entire question is extremely odd. 04 obviously refers to the interest rate. honestly i will say the answer is c. because the (2 x 12) part would mean it's compounded semiannually. i'll say choose c.