A figure is fully contained in Quadrant II, The figure is transformed as shown, a reflection over the x-axis, a reflection over the line y =x, and a 90° counterclockwise rotation about the origin.
In which quadrant does the resulting image lie?

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft

1/6

step-by-step explanation:

the second option

step-by-step explanation:

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629