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9514 1404 393

  91 rad/s

Step-by-step explanation:

The relationship between angular velocity (ω) and constant angular acceleration (ω') is ...

  ω(t) = ω0 + t·ω'

  ω(0.25) = 95 = ω0 + 0.25(16)

  95 -4 = ω0 = 91 . . . rad/s

The initial angular speed was 91 radians per second.

goog may be able to you find that answer

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584