Determine how many house alarm passcodes are available if characters
can be repeated and the code
contains 3 letters and 4 numbers.

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb

d. 145*2 is 290 than the total angle is 360 then minus 290 then divide by two

step-by-step explanation: