Work out the size of angle BCD

sin62=BD/AB

BD=Sin62×AB

BD=Sin62×15

BD=13.24

ALSO,

Tan C = BD/BC

Tan C = 13.24/24

Tan C = 5.51 / 10

C = Tan^-1 ( 5.51 / 10 )

∠BCD = 29°

Step-by-step explanation:

sin 62 = BD/15

0.8829 = BD/15

BD = 13.24

tan ∠BCD = 13.24/24 = 0.5517

∠BCD = 29°

idk but i found this "the graph of y = f(x-2) is the graph of y = f(x) translated two units rightward.  

so, since the point (9,2) lies on the graph of y = f(x), the point (11,2) lies on the graph of y = f(x-2)."

step-by-step explanation:

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the two may have that, even a breakdown is probably offered