A test is divided into 4 sets of problems with the same number of problems in each set. Alice correctly solves 35 problems. How many problems are on the test if Alice solved more than 60 percent of the problems, but less that 65 percent of all problems? Give all possible answers.

Step-by-step explanation:

The number is between

and

and

Possible numbers are:

Only one of the numbers, 56 is divisible by 4

The possible number of question are

232,228,224, and 220.

Step-by-step explanation:

Given that Alice correctly solves 35 problems

From the statement, 35 represents between 60 and 65 percent of the whole problem.

Let x be the total number of questions and choose 61% as the percentage Alice solved then,

61% of x = 35

0.61x = 35

x = 35/0.61

= 57.37

Aproximately 57

The possible answer are 58, 57, 56, 55

Since this represent 1 part, the question on test are:

54 * 4 = 232

or

57 * 4 = 228

or

56 * 4 = 224

or

55 * 4 = 220

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d

step-by-step explanation:

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.