The 1st 3 terms of an A. P., a, a+d, and a+2d, are the same as the 1st 3 terms of a G. P.( a is not equal to 0). Show that this is only possible if r=1 and d=0

See Below.

Step-by-step explanation:

The first three terms of an A.P is equivalent to the first three terms of a G.P.

We want to show that this is only possible if r = 1 and d = 0.

If a is the initial term and d is the common difference, the A.P. will be:

Likewise, for the G.P., if a is the initial term (and it does not equal 0) and r is the common ratio, then our sequence is:

The second and third terms must be equivalent. Thus:

We can cancel the d. Multiply the first equation by -2:

We can now add this to the second equation:

Simplify:

Now, we can divide both sides by a (we can do this since a is not 0):

So:

Factor:

Thus:

The first equation tells us that:

Therefore:

Hence:

Q.E.D.

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1

slope= 1

y-inter slope= 0

x       y

o     0

1       1

2     2

ect.

step-by-step explanation: