There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is congruent to side CD. If ∠BAC ≅ ∠DCA, the Choose... theorem can be used to show that △ABE ≅ △CDE.

SAS theorem

Step-by-step explanation:

Given

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

and

So, the congruent sides and angles of △ABE and △CDE are:

---- S

---- A

or  --- S

Hence, the theorem that compares both triangles is the SAS theorem

a.

step-by-step explanation:

step 1 distribute 2 to every term in the parentheses

step 2 add 10 on both sides of the equal sign

you could deduce the conclusion directly using the facts pertaining to the specific situation.

hope this .