Part G What is the mean absolute deviation for Doctor A's data set on contacts? What is the mean absolute deviation for Doctor B's data set on contacts? Write a sentence comparing these two data sets using their mean absolute deviations.

The answer is "751.6 and 755.2"

Step-by-step explanation:

Please find the attached file given question:

calculating the mean value of corrective Lenses in Doctor A:

calculating the mean value of corrective Lenses in Doctor B:

you need to rotate this triangle about the origin 270 degrees clockwise to create the full square.

unless you made a typo, the answers are both a and c.

step-by-step explanation:

1.5/3 is .5 whereas 3/9 is .3333333 not proportional

22/33 is .66666 and 4/6 is also .66666 proportional

2/4 is .5 whereas 142/213 is .66666 not proportional

14/7 is 2 and 7/3.5 is also 2 proportional

you could've also checked it by doing this simple division:

if the larger fraction divides with the smaller fraction to equal 1, it is proportional. so let me show you what i mean:

when i divide 22/33 by 4/6 i get 1, so we know it is proportional, and it is the same with 14/7 and 7/3.5. now if i divide 3/9 by 1.5/3 i get .66666 so therefore we know it is not proportional.

there are many ways to do this so i wanted to show you some possible ways.