V) Find the perimeter of the rectangle whose length is 60m and breadth is 55m vi) Find the perimeter of a square room with side equal to 8m each.

Step-by-step explanation:

l = length

b = breadth

We know the length is twice the breadth, therefore l = 2b

We also know that the perimeter p = 60m and can also be expressed as a sum of its sides where p = l + l + b + b = 60 which simplified is:

60 = 2l + 2b

Now we have 2 variables, but thankfully we were given a ratio (l = 2b) relating the two. Substituting 2b in for l gives us:

60 = 2(2b) + 2b = 4b + 2b = 6b

60 = 6b

b = 10 m

Now that we know the breadth we can find the length:

l = 2b → l = 2(10) = 20 → l = 20 m

With a breadth of 10 m and a length of 20 m

yes the total will be same because in both of them the expression.is rearranged but their sign remains the same hence it hss just been shuffled

1260=3*6*7*10=3^2*2^2*7*5 perfect cude = 3^3*2^

step-by-step explanation: