2 rowing teams are having a race. Boat a had a head start crossing the start line first & traveling at a speed of 3 meters per second. Boat b waited and crossed the start line 6 seconds after boat a. The speed of boat b was 4.8 meters per second.

Question:

Two rowing teams are having a race. Boat A had a head start, crossing the start line first and traveling at a speed of 3 meters per second. Boat B waited and then crossed the start line 6 seconds after Boat A. The speed of Boat B was 4.8 meters per second.

Part A- Write two equations, one for Boat A and one for Boat B. In both equations, let t equal the time in seconds since Boat A crossed the start line and d equal the distance traveled in meters.

Part B- Solve the system of equations from part A. show your work

A. Equations

b.

Step-by-step explanation:

For Boat A:

For Boat B:

Boat B waited 6 seconds later. So, the time is:

Solving (a): Equations

Speed is calculated as:

For Boat A:

Make d the subject

For Boat B:

Make d the subject

Substitute t - 6 for T

Hence, the equations are:

Solving (b): The value of d

Substitute 3t for d in the second equation

Collect like terms

Solve for t

Recall that:

Next, calculate the distance:

So:

Boat A travels for 16 seconds

Boat B travels for 10 seconds

The distance is 48km

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)