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Mathematics, 12.03.2021 20:00 manman71

The work of a student trying to solve the equation 2(2x βˆ’ 3) = 6 + 2x + 4 is shown below: Step 1: 2(2x βˆ’ 3) = 6 + 2x + 4
Step 2: 4x βˆ’ 3 = 10 + 2x
Step 3: 4x βˆ’ 2x = 10 + 3
Step 4: 2x = 13
Step 5: x = 6.5

In which step did the student first make an error and what is the correct step? (4 points)

Group of answer choices

Step 3: 4x + 2x = 10 + 3
Step 2: 4x βˆ’ 3 = 2 + 2x
Step 3: 4x βˆ’ 2x = 10 - 3
Step 2: 4x βˆ’ 6 = 10 + 2x

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Answers: 2

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The work of a student trying to solve the equation 2(2x βˆ’ 3) = 6 + 2x + 4 is shown below: Step 1: 2...
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