Make d the subject of the formula where d is positive
-5d + y = 6dc + 5a

if 5 + 6c is not 0.

Step-by-step explanation:

-5d + y = 6dc + 5a

first let's move all d's to one side and the rest to the other

-5d -6dc = 5a - y

5d + 6dc = y - 5a

d(5 + 6c) = y - 5a

if (5 + 6c) isn't 0:

d =

Step-by-step explanation:

Given

- 5d + y = 6dc + 5a ( subtract 6dc from both sides )

- 5d - 6dc = 5a - y ← factor out - d from each term on the left

- d(5 + 6c) = 5a - y ( multiply through by - 1 )

d(5 + 6c) = y - 5a ← divide both sides by (5 + 6c)

d =

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation: