15. Find the force on an electron crossing a uniform magnetic field of intensity 0.5 T WILII velocity of 106 ms-1. The charge carried by the electron is -1.6 x 10-19C.​

F = 8.48 x N

Step-by-step explanation:

The force on an electron in a magnetic field can be determined by;

F = qvB Sin θ

where: e is the electron, v is its velocity, B is the measure of the magnetic field, and θ is the angle of its path.

Thus,

q = -1.6 x C

v = 106 m/s

B = 0.5 T

θ =

So that,

F = 1.6 x x 106 x 0.5

  = 8.48 x N

The force on the electron crossing the uniform magnetic field is 8.48 x N.

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.