Find the inverse of g(n) = n– 3 – 1
g-1 (n) = -(n − 3)3
Og 1 (n) = in
g-1 (n) = (n + 1)...
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Mathematics, 12.03.2021 09:30 AliceYT
Find the inverse of g(n) = n– 3 – 1
g-1 (n) = -(n − 3)3
Og 1 (n) = in
g-1 (n) = (n + 1): +3
g-? (n) = 3 + n]
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