Plz answer will mark brainliest

Step-by-step explanation:

w and d are the width and diagonal, respectively.

w = d/2 + 1 = (d+2)/2

Pythagorean theorem

w^2 + 8^2 = d^2

substitution

(d+2)^2/4 +64 = d^2

(d+2)^2 + 256 = 4d^2

d^2+4d+4 + 256 = 4d^2

3d^2-4d-260 = 0

Quadratic formula

d = [4±√( 4²-4(3)(-260))]/[2⋅3] = 10, -26/3

-26/3 is an extraneous solution, so d = 10 inches

w=d/2 +1 =6 inches

Ant‘s path = 8+6 = 14 inches

Beetle’s path = 10 inches

14 < 1.5(10)

Ant reaches food first.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

answer: about 22.67

step-by-step explanation: