In Exercises 49-52, find u*v, where 0(feta) is the angle between u and v. How to find mag - sqrt u*2 + v*2
How to find u*v - 0=cos*-1(u*v/|u||v|)
49. |u|=4, |v|=10, 0=2pi/3
50. |u|=100, |v|=250, 0=pi/6
51. |u|=9, |v|=36, 0=3pi/6
52. |u|=4, |v|=12, 0=pi/3

Plzzzz i beg u asap ! what is the equation of this graphed line? enter your answer in slope-intercept form in the box.

To find the extreme values of a function f(x.y) on a curve x-x(t), y y(t), treat f as a function of the single variable t and use the chain rule to find where df/dt is zero. in any other single-variable case, the extreme values of f are then found among the values at the critical points (points where df/dt is zero or fails to exist), and endpoints of the parameter domain. find the absolute maximum and minimum values of the following function on the given curves. use the parametric equations x=2cos t, y 2 sin t functions: curves: i) the semicircle x4,y20 i) the quarter circle x2+y-4, x20, y20 b, g(x,y)=xy

Solve: 3x+y=6 4x-2y=18 show all work !