PLEASE HELP Describe the transformations that take place between each equation and f(x)=x2 g(x)=(x-3)^2+6

g(x)=(x+5)^2-1

g(x)=x^2+5

g(x)=(x-1)^2+7

g(x)=(x+2)^2-2

g(x)=x2-21

g(x)=(x-4)^2+8

g(x)=x^2+4

g(x)=x^2-11

g(x)=(x+6)^2+7

For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius and height 2r minus the volume of two cones, each with a radius and height of r. a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is and the volume of each cone with radius r and height r is 1/3 pie r^3. so the volume of the cylinder minus the two cones is therefore, the volume of the cylinder is 4/3pie r^3 by cavalieri's principle. (fill in options are: r/2- r- 2r- an annulus- a circle -1/3pier^3- 2/3pier^3- 4/3pier^3- 5/3pier^3- 2pier^3- 4pier^3)