The distance between the points(-3, -5) and (2,7) on the coordinate plane is given as 5^2+ t^2. what us the value of t​

Step-by-step explanation:

so we can use + 25  as one expression and the find the distance between the points and set the expression equal to that number.  That's our strategy.

dist = the square root  of  +  

where x and y are the change in x2 to x1 and y2 to y1

P1 = ( -3, -5)

P2 = (2, 7 )

dist = square root of (  [2 -(-3) ]^2  + [7-(-5)]2)

dist = sq rt  ( 5^2 + 12^2 )

dist = sq rt ( 25 + 144)

dist = sq rt (169)

dist = 13

now set our eq.  equal to that number

+ 25 = 13

= -12

this is looking kinda bad, do you know complex numbers?

t = 0 + j 3.46410

hmmm  I'm wondering if you've  left out .. or forgotten some thing in the question?   :/

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|