A cone has a height of 15 inches and a radius of 12 inches. What is its volume?

V ≈ 7186 in³

Step-by-step explanation:

The volume of a cone of base radius r and height h is V = (1/3)(π)(r^2)(h).

When h = 15 in and r = 12 in, the volume of the cone is

V = (1/3)(π)(12 in)²·(15 in), or approximately V ≈ 7186 in³

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°