Three forces of sizes 15n,7n and 19n pulling at 120 degrees to each other are acting on a particle. What is the size of the resultant force and the direction

10.58 N

Step-by-step explanation:

Let us find component of these forces in x and y direction.

The solution along with diagram can be found in attachment.

We have found resultant in X- direction = 6√3 N

resultant in Y- direction = 2 N

therefore net force resultant force =

= 10.58 N

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

5050

hope this !