What is the standard form of the quadratic function y=3(x-6)^2 +12

y=3(x-6)^2+12

y=3x-18^2+12

y=3x-324+12

y=3x-336

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hope it helps

sorry if it doesn't

i'm sure goog can you get that answer

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2