I need help very fast please !

Jump discontinuity at x = -2 & infinite discontinuity at x = 0.

Step-by-step explanation:

Hi again,

In this example, we see that there is a jump discontinuity at x = -2 because the line hypothetically "jumps" from y = 2 to y = 0. (just a way to remember these terms)

In addition, there is an infinite discontinuity at x = 0 because the green function will become infinitely close to x = 0 but never crosses nor touches it.

Hope this explanation was helpful. Cheers.

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.