Find a polynomial function f(x) of degree 3 with real coefficients that satisfies the following conditions. Zero of 0 and zero of 1 having multiplicity 2; f(2)= 10
The polynomial function is f(x)=

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)

11) obtuse

13)right

15) acute

14 x 10 5

step-by-step explanation:

10 5 = 100,000

14x10,000 = 140,000