How can (a+3)2=a2+6a+9 be derived from the polynomial identity (a−3)2=a2−6a+9? A. Add 12a to both sides of (a−3)2=a2−6a+9.
B. Add 6 to both sides of (a−3)2=a2−6a+9.
C. Multiply both sides of (a−3)2=a2−6a+9 by −1.
D. Substitute −a for a on both sides of (a−3)2=a2−6a+9.

the expected value of the random variable : 0, 1 and 2

step-by-step explanation:

answer: the answer is 127 degrees

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.