the sum of three numbers is 60. one is ten more than the second number. It is also twice the third. find the numbers

Step-by-step explanation: Given that, The sum of two numbers is 60

ie, 1st no + 2nd no = 60

Let us assume that 1st no is ‘x’

then x + 2nd no = 60

=> 2nd no = 60 - x

According to question, 3 times the number is 12 more than the other

=> 3 * 1st no = 12 + 2nd no

=> 3 * x = 12 + (60 - x)

=> 3x = 12 + 60 - x

=> 3x + x = 72

=> 4x = 72

=> x = 72 / 4

=> x = 18

So 1st no = 18

And 2nd no = 60-x = 60–18 = 42

Varification:

=> 3 * 1st no = 12 + 2nd no

=> 3 * 18 = 12 + 42

=> 54 = 54

Varified

Ans: 18 and 42

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step-by-step explanation:

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answer: your answer is a