Larry deposits $36,000 into each of two savings accounts. Account I earns 2.6% interest compounded annually.
Account II earns 2.6% annual simple interest.
There are no additional deposits or withdrawals.
What is the sum of the balances of these accounts at the end of 9 years?

$89,779.37

$90,710.74

$90,958.61

$93,069.22

$90,710.74

Step-by-step explanation:

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

probability for j is 1/4

while

a is 1/6