The figure below shows two triangles on a coordinate grid: What set of transformations is performed on on triangle ABC to from triangle A’B’C’?

A. A 180-degree counterclockwise rotation about the origin, followed by a translation 5 units down

B. A translation 5 units down followed by a 180-degree counterclockwise rotation about the origin

C. A 270-degree counterclockwise rotation about the origin, followed by a translation 5 units to the right

D. A translation 5 units to the right, followed by a 270-degree counterclockwise rotation about the origin

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

see below

step-by-step explanation:

x+2> 6

subtract 2 from each side

x+2-2 > 6-2

x > 4

there is an open circle at 4 since is it is greater than and the line goes to the right

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.