Suppose a line that appears parallel to side BC¯¯¯¯¯¯¯¯ of △ABC intersects sides AB¯¯¯¯¯¯¯¯ and AC¯¯¯¯¯¯¯¯ at points X and Y respectively, and AXAB=12. How can you determine if the line is or is not parallel to BC¯¯¯¯¯¯¯¯? Explain.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

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step-by-step explanation:

the given 6 = w/p is equivalent to 6p = w, where w is the total area of the walls and p is the area covered by a single can of paint.

knowing that 6 cans of paint will be needed, 6p = w becomes 6(6) = w = 36.   this tells us that the total area to be painted is 36 square units.