Solve for x in the equation 2x2 + 3x-7 = x2 + 5x+39

x=1+√47 or x=1−√47 (Assuming that the "2x2" is 2x^2)

Step-by-step explanation:

Step 1: Subtract x^2+5x+39 from both sides.

2x2+3x−7−(x2+5x+39)=x2+5x+39−(x2+5x+39)

x2−2x−46=0

For this equation: a=1, b=-2, c=-46

1x2+−2x+−46=0

Step 2: Use quadratic formula with a=1, b=-2, c=-46.

x=1+√47 or x=1−√47

idk

step-by-step explanation:

0,0

step-by-step explanation: