0. A mountain climber ascends a mountain to its peak. The peak is 14,090 ft above sea level. The climber then descends 490 ft to meet a fellow climber. Find the climber’s elevation above sea level after meeting the other climber.

13,600 ft

14,580 ft

–13,600 ft

9,190 ft

13,600 feet above sea level

Step-by-step explanation:

The climber was at 14,090 feet above sea level, and then they went 490 feet closer to sea level to meet the other climber. Since they’re moving closer to sea level and you want to know how far *above* sea level they are, subtract 490 from 14,090. 14,090-490=13,600 feet above sea level

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

i did it myself and i got 4.2 (b) hope its right

step-by-step explanation: