Can anyone else answer this? Measure the dimensions of the parallelogram shown to the nearest ½ centimeter.
Which measurement is closest to the area of the parallelogram in square centimeters?
Choices:
40 cm²
45.5 cm²
34 cm²
56 cm²

ok Kirishima

The height of the triangle is 6.5cm

Step-by-step explanation:

First of all we need to use the formula to calculate the area of a triangle:

a = area = 45.5 cm²

b = base = 14 cm

h = height

a = (b * h) / 2

we replace with the known values

45.5cm² = (14cm * h) / 2

45.5cm² * 2 = 14cm * h

91cm² / 14cm = h

6.5cm = h

The height of the triangle is 6.5cm

40 cm I think

Step-by-step explanation:

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12