Consider circle E.
A
B
26
D
E
F
What is the mBC ?
mBC

Please help​

Step-by-step explanation:

< AEB + < BEC = 180° {BEING LINEAR PAIR }

26° + < BEC = 180°

< BEC = 180° - 26°

< BEC = 154°

ARC BC = < BEC ( relation between arc and central angle)

Arc BC = 154°

Hope it will help :)

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.