Triangle ABC is a right- angled triangle.
ADB is a straight line.
DA = DC
Angle BCD = 20°
Work out the size of the angle
marked x.
You must give reasons for each
stage of your working out

yeah

Step-by-step explanation:

Ruler graduated in centimetres and millimetres, ... You must write down all stages in your working. ... (a) Mark with arrows (>>) a pair of parallel lines. ... (d) Measure the size of angle y. 125 ... ADB is a straight line. DA = DC. Angle BCD = 20°. Work out the size of the angle marked x. You

x=35°

Step-by-step explanation:

∠A+∠B+∠C=180°(ASP)

In ΔCAD, DC=DA

so, ∠DAC=∠DCA( angles opposite to equal sides are equal)

∠B=90°(given)

So, ∠DCA= 180°-(90+20)= 70°

Since ∠DCA= ∠DAC,

2x= 70°

x=35°

is only a line? i think so

jml angle lkj & angle mj = lm