The height of a right cone is 3 inches shorter than the radius. What is the height of the cone if the volume is 17 cubic inches? a. 3.454 inches
b. 4.01 inches
c. 7.01 inches
d. 1.01 inches

1.03 inches

Step-by-step explanation:

Volume of a come = 1/3πr²h

If the height of a right cone is 3 inches shorter than the radius, then;

h = r - 3

Substitute

V = 1/3πr²(r-3)

Given that V = 17in^3

17 = 1/3πr²(r-3)

17*3 = 3.14r²(r-3)

51/3.14 = r²(r-3)

16.242 = r²(r-3)

r² = 16.242

r = √16.242

r = 4.03

Since h = r - 3

h = 4.03 - 3

h = 1.03 inches

hence the height is 1.03 inches

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.