subject
Mathematics, 08.03.2021 04:20 anonymousanon

3 87 PM(P) =
1.
P = 90,
19,2, 90 < p < 99;
1-95
5
1.
H(P) =
95 p= 100,
100 < p < 106;
106-2
P-105
105 5
HVH(P) =
p> 110.
AUCU AUSCH

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Answers: 3

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3 87 PM(P) =
1.
P = 90,
19,2, 90 < p < 99;
1-95
5
1.
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