How to solve a pythagorean theorem problem dealing with a square; The diagonal of the square is 11.3 meters and I am to find the perimeter of the square.

Step-by-step explanation:

Each side of the square is s meters long.

By the Pythagorean Theorem,

length of diagonal = √(s²+s²)  = √(2s²) = s√2 meters

s√2 =  11.3

s = 11.3/√2

perimeter = 4s = 45.2/√2 ≅ 31.96 meters

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