Plz help meh A creature on the moon throws a rock off a cliff. The height of the rock above the surface of the moon, in meters, t seconds after it is thrown is given by h(t) = -t^2 + 8t + 10. When does the rock hit the surface of the moon?
Plz give step by step solution.

Step-by-step explanation:

The rock will hit the surface when its height equals zero.

t^2-8t-10=0

t^2-8t=10

t^2-8t+16=10+16

(t-4)^2=26

t-4=+(26^(1/2))

t=4+(26^(1/2))

t=9.1s

step-by-step explanation:

consider an orange peel: if you want to try and lay it flat, you have to stretch it, we know exactly how things are being stretched or squashed at any given point. we have many different map projections because each has different patterns of some projections can even preserve certain features of the earth without

the answer is c: divide the arc's degree measure by 360°, then multiply by the circumference of the circle.