½ - {- 1/3 + [1/5 x (2/6 – 1/6)]} = – 9/5 [ - 2/5 + (- 3/5 – 1/5) – (7/5 – 13/5)] – 1/5 =
[ 8/7 – ½ - ( - 1/14 + 12/18) – (- 7/3 – 5/6) ] =
– { 2/3 + [1/5 – (2/7 + ¾) – 5/4 ] + 1 } =
½ - { 2/5 + [(1/7 – 1/8) – (1/4 – 1/5)] + ½ }

Como puedo resolver estas fracciones? de antemano gracias

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

12cm

the answer is d

if im not mistaking its

step-by-step explanation:  

a

step-by-step explanation:

the denominator cannot be the same as one of the factors.

8 denominator times 2 denominator = 16

and 7 numerator time 11 = 77

77/16= 77/16 ( they cannot be further simplified)