The verticals of the triangle shape are A (-2, 4) , B (-2,3) , and C (-5,2). If ABC is reflected across the line y = -1 to produce the image of A'B'C', What's the coordinate of B' after a reflection across the line y=-1? ​

Given:

The vertices of a triangle are A (-2, 4) , B (-2,3) , and C (-5,2).

Triangle ABC is reflected across the line y = -1 to produce the image of A'B'C'.

To find:

The coordinate of B' after a reflection across the line y=-1.

Solution:

If a figure is reflected across the line y=b, then

The given triangle ABC is reflected across the line y=-1. So, the rule of reflection is

The coordinates of point B are (-2,3). So,

Therefore, the coordinates of point B' are (-2,-5).

i think the answer is fried chicken ; >

step-by-step explanation:

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~