The vertices of a rectangle are (3, 1), (3, 5), (6, 5), and (6, 1). Find the perimeter of the rectangle

14units

Step-by-step explanation:

Let the vertices of a rectangle be A(3, 1), B(3, 5), C(6, 5), and D(6, 1).

Using the formula for calculating distance between two points;

AB =√(5-1)²+(3-3)²

AB = √4²

AB = 4

BC = √(5-5)²+(6-3)²

BC = √3²

BC =>3

CD = √(1-5)²+(6-6)²

CD = √(-4)²

CD = √16

CD = 4

AD= √(1-1)²+(6-3)²

AD = √3²

AD = √9

AD =3

Perimeter of the rectangle = AB+BC+BD+AD

Perimeter of the rectangle = 4+3+4+3

Perimeter of the rectangle = 14units

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step-by-step explanation: