In AFGH, f = 60 cm, g = 10 cm and h=62 cm. Find the measure of ZF to the nearest
degree.

Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠abc = 90◦, and ad = bc. say the perpendicular bisector to dc meets the perpendicular bisector to ab at p. then pa = pb and pc = pd. so the triangles pad and pbc have equal sides and are congruent. thus ∠pad = ∠pbc. but pab is isosceles, hence ∠pab = ∠pba. subtracting, gives x = ∠pad−∠pab = ∠pbc −∠pba = 90◦. this is a preposterous conclusion – just where is the mistake in the "proof" and why does the argument break down there?

Consider the following equation -167 + 37 = 49 - 21p select the equation that has the same solution as the given equation. o a. p - 5 + ip = 7 - p ob. +55 + 12p = 5p + 16 c. 2 + 1.25p = -3.75p + 10 d. -14 + 6p = -9 - 6p reset next

Elena is paid a constant rate for each hour she works. the table shows the amounts of money that elena earned for various amounts of time that she worked.