Consider this function in explicit form. f(n)=4⋅(12)n−2; n≥1
Select the equivalent recursively defined function.

f(1)=8f(n)=2⋅f(n−1);n≥2

f(1)=4f(n)=12⋅f(n−1);n≥2

f(1)=4f(n)=2⋅f(n−1);n≥2

f(1)=8f(n)=12⋅f(n−1);n≥2

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.