Brahmagupta's solution to a quadratic equation of the form ax? + bx = c involved only one solution. Which solution would he have found for the equation 3x2 + 4x = 6?
O x = 4(3)(6) +42-4
2(3)
2/22-4/22-2
6
3
x = 4(3)(4) +62 -6 - 2721-6.V21-3.
2/27 -6 - 121-3
2(3)
O x = 4(4)(6) + 32 - 3 V105 - 3
2(4)
8
x= √4 (3) (6) – 4² +4 2√14+4 +2
26)
6
3