Write 4y−10=0 in slope-intercept form

y=5/2

Step-by-step explanation:

y= 5/2

Step-by-step explanation:

4y-10=0

+10      +10    <-- add 10 to both sides

4y=10  

4y/4=10/4      <-- divide by 4 to isolate y

y=10/4    

y=5/2            <-- simplify

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(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180