A jar contains n nickels and d dimes. There is a total of 206 coins in the jar. The value of the coins is $13.95. How many nickels and how many dimes are in the jar? ​

73 dimes and 133 nickels

Step-by-step explanation:

$13.95 = 1395 cents

5n + 10d = 1395     (since each nickel is 5 cents and each dime is 10 cents)

5n = 1395 - 10d      (subtract 10d from both sides to solve for n)

n = 279 - 2d

n + d = 206

279 - 2d + d = 206   (substitute n with the previous expression)

279 - d = 206         (add variable d and -2d)

-d = -73        (solve for d and divide both sides by negative 1)

d = 73          

n + 73 = 206 (solve for n and subtract both sides by 73)  

n = 133

step-by-step explanation:

perimeter = 10 +  √10  units

explanation:

first, we will need to get the length of each line using the distance formula which is as follows:

distance = 

1- length of ab:

ab =   = 5 units

2- length of ac

length of ac is the same as ab = 5 units

3- length of bc:

bc =   =  √10  units

now, we can get the perimeter by adding the side lengths as follows:

perimeter = 5 + 5 +  √10

perimeter = 10 +  √10  units

hope this : )

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