Please help precalc Use trigonometric identities to solve each equation within the given domain.
1. –sin^2(x) = cos(2x) from [–π,π]

2. 3 tan(x) = 2 sin(2x) from [0,2π)

3. sec(x) cos(3x) = 0 from [–π /2, π /2]

4. sec(x) cos(3x) = 0 from [–π/2, π/2]

5. "4cos^4(x) – 5cos^2(x) + 1 = 0 from [0,2π)

the correct answers i think are b. and d.

give me brainliest if it is correct!

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!

y/x of point b= y/x of point a

step-by-step explanation:

(i got the same question, this was the correct answer.)