The center of a circle bs located at 3,9), and the evde hesa vedles that to sustain What the parengtame een hee) 0 #4 - 6 = 46 + 6 = ()
7* 9-6-167-15-6
0676x* 167 18-0
D. ** *64*167-15-0

The general equation of a circle is x2 + y2 - 6x - 16y + 48 = 0

Step-by-step explanation:

step-by-step explanation:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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