HELP The point (-10,4) is on the graph of which of these functions? Select ALL that apply.​

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Explanation:

We'll plug x = -10 into each equation shown. If we get y = 4 as an output, then it is one of the answers.

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A)

y = -x^2 + 6

y = -(-10)^2 + 6

y = -100 + 6

y = -94

We don't get y = 4, so we cross choice A off the list.

The point (-10,4) is not on y = -x^2+6. Instead, the point (-10,-94) is.

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B)

y = (-1/2)*x - 1

y = (-1/2)*(-10) - 1

y = 5 - 1

y = 4

We can see that x = -10 leads to y = 4. The point (x,y) = (-10,4) is on the line. Choice B is one of the answers.

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C)

y = (-1/10)*x - 3

y = (-1/10)*(-10) - 3

y = 1 - 3

y = -2

Choice C is not one of the answers since we want y = 4 as an output. So we can cross choice C off the list.

The point (-10,-2) is on the line instead of (-10,4)

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D)

y = (1/10)x + 5

y = (1/10)*(-10) + 5

y = -1 + 5

y = 4

Choice D is one of the answers

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E)

y = (1/5)*x^2 - 16

y = (1/5)*(-10)^2 - 16

y = (1/5)*(100) - 16

y = 20 - 16

y = 4

Choice E is one of the answers

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An alternative method is to graph each equation and see if (-10,4) is on the curve or not. See the diagram below. Only choices B, D and E have (-10,4) on their respective curves.

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

this linear equation would have just one solution.

step-by-step explanation:

the reason why this would have one solution is that it is an expression with just one variable. since that variable is not raised to a power, it will always have just one solution.