Jason purchased three different sizes of candy at the store. The medium candy was twice as expensive as the small candy. The large
candy was $5 more than the medium candy. He spent a total of $30 on
candy. Write and solve an equation to determine the cost of the small
candy.

$5

Step-by-step explanation:

Let the small candy be represented by x.

The medium candy was twice as expensive as the small candy. This will be: = 2×x = 2x

The large candy was $5 more than the medium candy. This will be: = 2x + 5

Since Jason spent a total of $30 on

candy, the cost of the small candy will be:

x + 2x + 2x + 5 = 30

5x + 5 = 30

5x = 30 - 5

5x = 25

x = 25/5

x= 5

The small candy cost $5

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3